5^x-1=5(2^x-2)

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Solution for 5^x-1=5(2^x-2) equation: 



5^x-1=5(2^x-2)

We move all terms to the left:

5^x-1-(5(2^x-2))=0



We calculate terms in parentheses: -(5(2^x-2)), so:

5(2^x-2)

We multiply parentheses

10x-10

Back to the equation:

-(10x-10)



We get rid of parentheses

5^x-10x+10-1=0

We add all the numbers together, and all the variables

-10x+5^x+9=0

We move all terms containing x to the left, all other terms to the right

-10x+5^x=-9

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